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Tuesday, January 5, 2016

P(B|E) = P(B) X P(E|B) / P(E)



John Horgan took a good whack yesterday at explaining much-heralded Bayes Theorem (includes several good links, and be sure to read the comments section as well):

http://blogs.scientificamerican.com/cross-check/bayes-s-theorem-what-s-the-big-deal/


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