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Friday, August 17, 2012

Friday Puzzle


First, a note to my regular readers… all 3 of you ;-))

My usual format here has been to gather math-related material I find interesting from around the Web and then parse it out, 1 post per day, through the week over 5 or 6 days, usually setting aside Friday as a "puzzle" day. Starting now(!), things will be less standardized. I'll post things in a more free-form way… there could be 2 or even 3 posts in a single day, or several days with no posts; or, a single post might include multiple unrelated topics and links. And Friday will no longer be relegated to puzzles, though I'll still post puzzles from time-to-time, in a more random manner.

Trying this out just to make things less regimented and more easy/flexible at my end, without set timetables. If it doesn't work well, can always revert to the old style.
None of this will likely much affect those of you getting an RSS feed, but if you're in a habit of checking this blog each morning (when I usually post) or only stopping by on Fridays for the puzzle, it may alter your routine.

With all that said, one last easy Friday thought puzzle for now:

When my digital clock shows 2:35 a.m. it is the very first time past midnight that 3 and only 3 different prime numbers appear. What will be the last time before noon when all 3 numbers on the digital readout are different prime numbers?
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.ANSWER below....
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. ANSWER:

7:53

1 comment:

.mau. said...

if you consider the hour as a single number, 11:53 could be also okay :-)

(this said, I agree with you in not having a fixed schedule, but I liked the idea of a Friday puzzle. On my own blog I have the Sunday puzzles, and I prepare them well in advance...)