## Friday, March 2, 2012

### Friday Probability Conundrum

First, here's a review of a new book that may be of interest to puzzle-solvers:

http://www.newscientist.com/blogs/culturelab/2012/03/the-secrets-of-solving-mathematical-puzzles.html

And now, on to a Friday blog puzzle: I adapted this one from another recent Car Talk puzzler, and I like it a lot as another Marilyn vos Savant-type simple (...but not quite so simple) probability dilemma. In fact I've re-written it into a 'Monty Hall'-like framework:

Monty Hall shows you 3 cards, one that is the color red on both sides, one that is green on both sides, and one that is red on 1 side and green on the other side. He puts all 3 into a black bag and shuffles them around. A blindfolded assistant randomly pulls out one card from the bag and lays it flat on the table so only the top side is observable. That side is red. You as a contestant can only win a prize if you accurately guess the color of the card's opposite unseen side. Should you guess red, green, or are your chances equal whichever you guess?